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Find the area of ABC whose vertices are A(1, 2), B(-2, 3) and

Question

Find the area of $Δ A BC$ whose vertices are $A (1, 2), B (- 2, 3)$ and $C (- 3, - 4)$ .

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Find the area of

Δ A BC

whose vertices are

A (1, 2), B (- 2, 3)

and

C (- 3, - 4)

12 mins ago

Discuss this question LIVE

12 mins ago

Text solutionVerified

Area of

Δ A BC

whose vertices are is

(x_{1}, y_{1}), (x_{2}, y_{2})

and

(x_{3}, y_{3})

are

Area of

Δ A BC = \frac{1}{2} [x_{1} (y_{2} - y_{3}) + x_{2} (y_{3} - y_{1}) + x_{3} (y_{1} - y_{2})]

Δ A BC

, vertices are

A (1, 2), B (- 2, 3)

and

C (- 3, - 4)

Area of triangle

= 1/2 (1 (- 2 + 3) - 2 (- 4 - 2) - 3 (2 - 3))

= 1/2 (1 + 12 + 3)

= 8

sq units.

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Question Text	Find the area of $Δ A BC$ whose vertices are $A (1, 2), B (- 2, 3)$ and $C (- 3, - 4)$ .
Answer Type	Text solution:1
Upvotes	150