Find the 25th term of the AP 5,421,4,321,3,......

Given AP is5,421,4,321,3,....Here, first term =a=5Common difference:d=421−5=2−1nth term is given by,an=a+(n−1)dPut n=25a25=5+(25−1)(−1/2)=−7.

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Find the 25th term of the AP 5, 4{1}{2}, 4, 3{1}{2}, 3, ......

Question

Find the $25$ th term of the AP $5, 4 \frac{1}{2}, 4, 3 \frac{1}{2}, 3, .....$ .

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Levi Discussed

Find the

25

th term of the AP

5, 4 \frac{1}{2}, 4, 3 \frac{1}{2}, 3, .....

11 mins ago

Discuss this question LIVE

11 mins ago

Given AP is

5, 4 \frac{1}{2}, 4, 3 \frac{1}{2}, 3, ....

Here, first term

= a = 5

Common difference:

d = 4 \frac{1}{2} - 5 = \frac{- 1}{2}

n^{t h}

term is given by,

a_{n} = a + (n - 1) d

Put

n = 25

a_{25} = 5 + (25 - 1) (- 1/2)

= - 7

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Question Text	Find the $25$ th term of the AP $5, 4 \frac{1}{2}, 4, 3 \frac{1}{2}, 3, .....$ .
Answer Type	Text solution:1
Upvotes	150