Evaluate : (cos229∘+cos261∘)3cos53∘cosec37∘−3tan245∘

(cos229∘+cos261∘)3cos53∘ cosec37∘−3tan245∘= (cos229∘+cos2(90− 29)∘)3cos53∘cosec (90−53)∘−3tan245∘= (cos229∘+sin229∘)3cos53∘sec53∘−3tan245∘= 13−3(1)2= 0

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Evaluate : {3 53^{} {cosec}37^{}}{( ^{2}29^{}+ ^{2}61^{})}-3

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Evaluate : $\frac{3 cos 5 3 ^{\circ} cosec 3 7 ^{\circ}}{( cos ^{2} 2 9 ^{\circ} + cos ^{2} 6 1 ^{\circ} )} - 3 tan^{2} 4 5^{\circ}$

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\frac{3 cos 5 3 ^{\circ} cosec 3 7 ^{\circ}}{( cos ^{2} 2 9 ^{\circ} + cos ^{2} 6 1 ^{\circ} )} - 3 tan^{2} 4 5^{\circ}

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\frac{3 cos 5 3 ^{\circ} cosec 3 7 ^{\circ}}{( cos ^{2} 2 9 ^{\circ} + cos ^{2} 6 1 ^{\circ} )} - 3 tan^{2} 4 5^{\circ}

\frac{3 cos 5 3 ^{\circ} cosec ( 90 - 53 ) ^{\circ}}{( cos ^{2} 2 9 ^{\circ} + cos ^{2} ( 90 - 29 ) ^{\circ} )} - 3 tan^{2} 4 5^{\circ}

\frac{3 cos 5 3 ^{\circ} sec 5 3 ^{\circ}}{( cos ^{2} 2 9 ^{\circ} + sin ^{2} 2 9 ^{\circ} )} - 3 tan^{2} 4 5^{\circ}

\frac{3}{1} - 3 (1)^{2}

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Question Text	Evaluate : $\frac{3 cos 5 3 ^{\circ} cosec 3 7 ^{\circ}}{( cos ^{2} 2 9 ^{\circ} + cos ^{2} 6 1 ^{\circ} )} - 3 tan^{2} 4 5^{\circ}$
Answer Type	Text solution:1
Upvotes	150

Evaluate : (cos229∘+cos261∘)3cos53∘cosec37∘​−3tan245∘

Text solutionVerified

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Evaluate : $\frac{3 cos 5 3 ^{\circ} cosec 3 7 ^{\circ}}{( cos ^{2} 2 9 ^{\circ} + cos ^{2} 6 1 ^{\circ} )} - 3 tan^{2} 4 5^{\circ}$