Evaluate $cos 4 8^{o} cos 4 2^{o} - sin 4 8^{o} sin 4 2^{o}$

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cos 4 8^{o} cos 4 2^{o} - sin 4 8^{o} sin 4 2^{o}

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cos 4 8^{o} cos 4 2^{o} - sin 4 8^{o} sin 4 2^{o} = cos (9 0^{o} - 4 2^{o}) cos (9 0^{o} - 4 8^{o}) - sin 4 8^{o} sin 4 2^{o}

= sin 4 2^{o} sin 4 8^{o} - sin 4 8^{o} sin 4 2^{o} [∵ cos (90 - θ) = sin θ]

= 0

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