Draw a △ABC with side BC=7 cm, ∠B=45∘,∠A=105∘. Then, construct a triangle whose sides are 34 times the corresponding sides of △ABC.

Question

Draw a △ABC with side BC=7 cm, ∠B=45∘,∠A=105∘. Then, construct a triangle whose sides are 34​ times the corresponding sides of △ABC.

Filo · Accepted Answer

In △ABC, ∠A+∠B+∠C=180∘∴105∘+45∘+∠C=180∘∴∠C=30∘Constructing △ABC:Step 1: Draw base BC of length 7 cm.Step 2: Draw a ray at an angle of 45∘ with line BC from point B.Step 3: Draw a ray at an angle of 30∘ from line CB from point C and mark the intersection point of the rays from B and C as A.Step 4: Join A−B and A−C. △ABC is the required triangle.For constructing △EBD∼△ABCStep 1: Draw a ray BX at an acute angle to line BC on the opposite side of A.Step 2: Mark 4 equidistant points B1​,B2​,B3​,B4​ on ray BX.Step 3: Join B3​ and C.Step 4: Draw B4​D parallel to B3​C and label the intersection on the extension of BC as D.Step 5: Draw DE parallel to BA and label the intersection with the extension of BA as E△EBD is the required triangle.

Question Text	Draw a $△ A BC$ with side $BC = 7 c m$ , $∠ B = 45^{\circ}, ∠ A = 105^{\circ}$ . Then, construct a triangle whose sides are $\frac{4}{3}$ times the corresponding sides of $△ A BC$ .
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Draw a $△ A BC$ with side $BC = 7 c m$ , $∠ B = 45^{\circ}, ∠ A = 105^{\circ}$ . Then, construct a triangle whose sides are $\frac{4}{3}$ times the corresponding sides of $△ A BC$ .

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Practice questions from similar books

Draw a △ABC with side BC=7 cm, ∠B=45∘,∠A=105∘. Then, construct a triangle whose sides are 34​ times the corresponding sides of △ABC.

Text solutionVerified

Practice questions from similar books

Draw a $△ A BC$ with side $BC = 7 c m$ , $∠ B = 45^{\circ}, ∠ A = 105^{\circ}$ . Then, construct a triangle whose sides are $\frac{4}{3}$ times the corresponding sides of $△ A BC$ .