secθ1= _____ for an acute angle θ in a right angled triangle.

sinθ=hypotenuseopposite cosθ=hypotenuseadjacent sec θ=adjacenthypotenusesec θ1=adjacenthypotenuse1=hypotenuseadjacent=cos θ∴ sec θ1=cos θ

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{1}{{}} = _____ for an acute angle in a right angled triangle

Question

$\frac{1}{sec θ} =$ _____ for an acute angle $θ$ in a right angled triangle.

cos θ

sin θ

tan θ

None of these

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\frac{1}{sec θ} =

_____ for an acute angle

θ

in a right angled triangle.

13 mins ago

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13 mins ago

sin θ = \frac{o pp os i t e}{h y p o t e n u se}

cos θ = \frac{a d ja ce n t}{h y p o t e n u se}

sec θ = \frac{h y p o t e n u se}{a d ja ce n t}

\frac{1}{sec θ} = \frac{1}{\frac{h y p o t e n u se}{a d ja ce n t}} = \frac{a d ja ce n t}{h y p o t e n u se} = cos θ

∴ \frac{1}{sec θ} = cos θ

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Question Text	$\frac{1}{sec θ} =$ _____ for an acute angle $θ$ in a right angled triangle.
Answer Type	Text solution:1
Upvotes	150