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Construct a triangle PQR in which {Q}={30}^{o}, {R}={90}^{o}

Question

Construct a triangle $PQR$ in which $∠ Q = 30^{o}$ , $∠ R = 90^{o}$ and $PQ + QR + PR = 11 c m$ .

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Sebastian Discussed

Construct a triangle

PQR

in which

∠ Q = 30^{o}

∠ R = 90^{o}

and

PQ + QR + PR = 11 c m

13 mins ago

Discuss this question LIVE

13 mins ago

Text solutionVerified

Steps of Construction:

1. Draw a line segment

A B = 11 c m

(= PQ + QR + RP)

2. At

A

, construct an angle of

3 0^{\circ}

and at

B

, an angle of

9 0^{\circ}

3. Bisect these angles. Let the bisectors of these angles intersect at a point

P

4. Draw perpendicular bisectors

D E

A P

to intersect

A B

Q

and

FG

PB

to intersect

A B

R

5. Join

PQ

and

PR

. Then,

PQR

is the required triangle.

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Question Text	Construct a triangle $PQR$ in which $∠ Q = 30^{o}$ , $∠ R = 90^{o}$ and $PQ + QR + PR = 11 c m$ .
Answer Type	Text solution:1
Upvotes	151

Construct a triangle PQR in which ∠Q=30o, ∠R=90o and PQ+QR+PR=11cm.

Text solutionVerified

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Construct a triangle $PQR$ in which $∠ Q = 30^{o}$ , $∠ R = 90^{o}$ and $PQ + QR + PR = 11 c m$ .