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and are two right triangles with common hypotenuse . Prove that .
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Given,
AC is the common hypotenuse. .
To prove,
Proof:
Since, and are .
These angles are in the semi-circle.
Thus, both the triangles are lying in the semi-circle and is the diameter of the circle.
⇒ Points and are concyclic.
Thus, is the chord.
...Angles in the same segment of the circle
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| Question Text | and are two right triangles with common hypotenuse . Prove that . |
| Answer Type | Text solution:1 |
| Upvotes | 150 |
