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A jar contains 24 marbles, some are green and others are blue.

Question

A jar contains $24$ marbles, some are green and others are blue. If a marble is drawn at random from the jar, the probability that it is green is $\frac{2}{3}$ . Find the number of blue balls in the jar.

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Liam Discussed

A jar contains

24

marbles, some are green and others are blue. If a marble is drawn at random from the jar, the probability that it is green is

\frac{2}{3}

. Find the number of blue balls in the jar.

7 mins ago

Discuss this question LIVE

7 mins ago

Text solutionVerified

Total number of marbles

= 24

Let there be

x

green marbles and

(24 - x)

blue marbles.

P(green)

= \frac{x}{24} = \frac{2}{3}

Solving, we get

x

16.

So, the number of green marbles

= 16

and blue marbles

= 24 - 16 = 8

marbles.

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Question Text	A jar contains $24$ marbles, some are green and others are blue. If a marble is drawn at random from the jar, the probability that it is green is $\frac{2}{3}$ . Find the number of blue balls in the jar.
Answer Type	Text solution:1
Upvotes	150