A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: Rs. 200 for the first day, Rs. 250 for the second day, Rs. 300 for the third day, etc., the penalty for each succeeding day being Rs. 50 more than for the preceding day. How much money the contractor has to pay as penalty, if he has delayed the work by 30 days.

Question

Filo · Accepted Answer

It can be observed that these penalties are in an A.P. having first term as

200

and common difference as

50

.

a = 200, d = 50

S u m u pt o n t er m s

(S_{n}) = \frac{n}{2} [2 a + (n - 1) d]

Penalty that has to be paid if he has delayed the work by

30

days

= S_{30}

=

S_{30} = \frac{30}{2} [2 (200) + (30 - 1) 50]

= 15 [400 + 1450]

= 15 (1850)

= 27750

Therefore, the contractor has to pay Rs

27750

as penalty.

Question Text	A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: Rs. $200$ for the first day, Rs. $250$ for the second day, Rs. $300$ for the third day, etc., the penalty for each succeeding day being Rs. $50$ more than for the preceding day. How much money the contractor has to pay as penalty, if he has delayed the work by $30$ days.
Answer Type	Text solution:1
Upvotes	150

Text solutionVerified

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