A and B are two events such that P(A)=0.54, P(B)=0.69and P(A∩B)=0.35.Find (i) P(A∪B) (ii) P(Aprime∩Bprime) (iii) P(A∩Bprime) (iv) P(B∩Aprime)

Solution: (i)P(A∪B)=P(A)+P(B)−P(A∩B)=0.54+0.69−0.35=0.88(ii)P(A′∩B′)=1−P(A∪B)=1−0.88=0.12(iii)P(A∩B′)=P(A)−P(A∩B)=0.54−0.35=0.19(iv)P(B∩A′)=P(B)−P(B∩A)=0.69−0.35=0.34

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A and B are two events such that {P}{({A})}={0}.{54}, {P}{({B}

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A and B are two events such that $P (A) = 0.54$ , $P (B) = 0.69$ and $P (A \cap B) = 0.35$ .Find
(i) $P (A \cup B)$
(ii) $P (A^{p r i m e} \cap B^{p r i m e})$
(iii) $P (A \cap B^{p r i m e})$
(iv) $P (B \cap A^{p r i m e})$

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Harper Discussed

A and B are two events such that

P (A) = 0.54

P (B) = 0.69

and

P (A \cap B) = 0.35

.Find
(i)

P (A \cup B)

(ii)

P (A^{p r i m e} \cap B^{p r i m e})

(iii)

P (A \cap B^{p r i m e})

(iv)

P (B \cap A^{p r i m e})

13 mins ago

Discuss this question LIVE

13 mins ago

Text solutionVerified

Solution: (i)

P (A \cup B) = P (A) + P (B) - P (A \cap B)

= 0.54 + 0.69 - 0.35 = 0.88

(ii)

P (A^{'} \cap B^{'}) = 1 - P (A \cup B) = 1 - 0.88 = 0.12

(iii)

P (A \cap B^{'}) = P (A) - P (A \cap B) = 0.54 - 0.35 = 0.19

(iv)

P (B \cap A^{'}) = P (B) - P (B \cap A) = 0.69 - 0.35 = 0.34

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Question Text	A and B are two events such that $P (A) = 0.54$ , $P (B) = 0.69$ and $P (A \cap B) = 0.35$ .Find (i) $P (A \cup B)$ (ii) $P (A^{p r i m e} \cap B^{p r i m e})$ (iii) $P (A \cap B^{p r i m e})$ (iv) $P (B \cap A^{p r i m e})$
Answer Type	Text solution:1
Upvotes	150

A and B are two events such that P(A)=0.54, P(B)=0.69and P(A∩B)=0.35.Find (i) P(A∪B) (ii) P(Aprime∩Bprime) (iii) P(A∩Bprime) (iv) P(B∩Aprime)

Text solutionVerified

Practice questions from similar books

A and B are two events such that $P (A) = 0.54$ , $P (B) = 0.69$ and $P (A \cap B) = 0.35$ .Find
(i) $P (A \cup B)$
(ii) $P (A^{p r i m e} \cap B^{p r i m e})$
(iii) $P (A \cap B^{p r i m e})$
(iv) $P (B \cap A^{p r i m e})$