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What is the value of the absolute zero of temperature on their

Question

What is the value of the absolute zero of temperature on their temperature scale?

A

233.3 3^{o}

C

B

- 233.3 3^{o}

C

C

- 233.3 3^{o}

N

D

233.3 3^{o}

N

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Text solutionVerified

Given,
Here

N

denotes Newton Degree. One Newton Degree is equal to

\frac{33}{100}^{o} C

.

Melting point

= 0^{o}

N

Boiling point

= 10 0^{o}

N

given the value A

P V_{m} = 28

at

0^{o}

N

P V_{m} = 40

at

10 0^{o}

N

Using ideal gas equation for reduced volume,

n = 1

also taking the absolute value as x.

∴ 28 = R (x + 0)

(at

0^{o}

N)

\Rightarrow R x = 28

…….

(1)

at

10 0^{o}

N

40 = R (x + 100)

\Rightarrow 40 = R x + R \times 100

R \times 100 = 40 - 28

R = \frac{12}{100} = 0.12

On putting back in equation

(1)

we get

x = \frac{28 \times 100}{12}

\Rightarrow x = 233.33

In general absoulte zero is

0 K

or

- 273^{o} C

[K] = [^{o} C] + 273

Similarly, here

[K] = [^{o} N] + 233

∴

Absolute Zero is

- x

- x = - 233.33

Option C.

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Question Text	What is the value of the absolute zero of temperature on their temperature scale?
Answer Type	Text solution:1
Upvotes	150