The temperature of a gas at pressure P and volume V is 27∘C . Keeping its volume constant if its temperature is raised to 927∘C, then its pressure will be

The gas equation states that,PV=nRTSo, we can conclude that,P∝THence, P2P1=T2T1Given, T1=300K,T2=1200,P1=P∴P2=T1P1T2⇒P2=300P×1200⇒P2=4P is our required answer.

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The temperature of a gas at pressure P and volume V is 27^{} C

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The temperature of a gas at pressure $P$ and volume V is $2 7^{\circ} C$ . Keeping its volume constant if its temperature is raised to $92 7^{\circ} C,$ then its pressure will be

2 P

3 P

4 P

6 P

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The temperature of a gas at pressure

P

and volume V is

2 7^{\circ} C

. Keeping its volume constant if its temperature is raised to

92 7^{\circ} C,

then its pressure will be

11 mins ago

Discuss this question LIVE

11 mins ago

Text solutionVerified

The gas equation states that,

P V = n RT

So, we can conclude that,

P \propto T

Hence,

\frac{P _{1}}{P _{2}} = \frac{T _{1}}{T 2}

Given,

T_{1} = 300 K, T_{2} = 1200, P_{1} = P

∴ P_{2} = \frac{P _{1} T _{2}}{T _{1}}

\Rightarrow P_{2} = \frac{P \times 1200}{300}

\Rightarrow P_{2} = 4 P

is our required answer.

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Question Text	The temperature of a gas at pressure $P$ and volume V is $2 7^{\circ} C$ . Keeping its volume constant if its temperature is raised to $92 7^{\circ} C,$ then its pressure will be
Answer Type	Text solution:1
Upvotes	150

The temperature of a gas at pressure P and volume V is 27∘C . Keeping its volume constant if its temperature is raised to 927∘C, then its pressure will be

Text solutionVerified

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The temperature of a gas at pressure $P$ and volume V is $2 7^{\circ} C$ . Keeping its volume constant if its temperature is raised to $92 7^{\circ} C,$ then its pressure will be