The oxide of a metal (R) can be reduced by the metal (P) and metal (R) can reduce the oxide of metal (Q). Then the decreasing order of the reactivity of metal (P), (Q) and (R) with oxygen is :

P > Q > R

P > R > Q

R > P > Q

Q > P > R

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The oxide of a metal (R) can be reduced by the metal (P) and metal (R) can reduce the oxide of metal (Q). Then the decreasing order of the reactivity of metal (P), (Q) and (R) with oxygen is :

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Text solutionVerified

As R can reduce oxide of Q, so R is more reactive than Q.

P can reduce oxide of R so P is more reactive than R.
So, reactivity order is P > R > Q.

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Question Text	The oxide of a metal (R) can be reduced by the metal (P) and metal (R) can reduce the oxide of metal (Q). Then the decreasing order of the reactivity of metal (P), (Q) and (R) with oxygen is :
Answer Type	Text solution:1
Upvotes	150

The oxide of a metal (R) can be reduced by the metal (P) and metal (R) can reduce the oxide of metal (Q). Then the decreasing order of the reactivity of metal (P), (Q) and (R) with oxygen is :

Text solutionVerified

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