The Hydrolysis constant of MX is (Given, Kb of MOH is 2×10−6 and Ka of HX is 5×10−7)

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The Hydrolysis constant of {M}{X} is (Given, {K}_{{{b}}} of {M

Question

The Hydrolysis constant of $M X$ is (Given, $K_{b}$ of $M O H$ is $2 \times 10^{- 6}$ and $K_{a}$ of $H X$ is $5 \times 10^{- 7})$

10^{2}

10^{- 2}

10^{- 3}

10^{3}

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The Hydrolysis constant of

M X

is (Given,

K_{b}

M O H

2 \times 10^{- 6}

and

K_{a}

H X

5 \times 10^{- 7})

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Question Text	The Hydrolysis constant of $M X$ is (Given, $K_{b}$ of $M O H$ is $2 \times 10^{- 6}$ and $K_{a}$ of $H X$ is $5 \times 10^{- 7})$
Answer Type	Video solution: 1
Upvotes	151