The hybridization of atomic orbitals of nitrogen is $N O_{2}^{+}, N O_{3}^{-}$ , and $N H_{4}^{+}$ respectively are

s p, s p^{3}, and s p^{2}

respectively

s p, s p^{2}, and s p^{3}

respectively

s p^{2}, s p, and s p^{3}

rspectively

s p^{2}, s p^{3}, and s p

respectively

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The hybridization of atomic orbitals of nitrogen is

N O_{2}^{+}, N O_{3}^{-}

, and

N H_{4}^{+}

respectively are

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Question Text

The hybridization of atomic orbitals of nitrogen is

N O_{2}^{+}, N O_{3}^{-}

, and

N H_{4}^{+}

respectively are

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