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The decomposition of phosphine (PH_3) on tungsten at low press

Question

The decomposition of phosphine $(P H_{3})$ on tungsten at low pressure is a first-order reaction. It is because the:

rate is independent of the surface coverage

rate of decomposition is very slow

rate is proportional to the surface coverage

rate is inversely proportional to the surface coverage

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The decomposition of phosphine

(P H_{3})

on tungsten at low pressure is a first-order reaction. It is because the:

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Text solutionVerified

The decomposition of

P H_{3}

on tungsten at low pressure is a first order reaction because surface area coverage is proportional to partial pressure of

P H_{3}

. Hence, rate is proportional to the surface coverage.

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Question Text	The decomposition of phosphine $(P H_{3})$ on tungsten at low pressure is a first-order reaction. It is because the:
Answer Type	Text solution:1
Upvotes	154