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Vapour pressure of liqid solution

Relative lowering of vapour pressure of an aqueous glucose dil

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Medium

Solving time: 3 mins

Relative lowering of vapour pressure of an aqueous glucose dilute solution is found to be 0.018. Hence, elevation in boiling point is (Given, that 1 molal aqueous urea solution boils at $00.05 4^{\circ} C$ at 1 atm pressure).

0.01 8^{\circ} C

0.1 8^{\circ} C

0.5 4^{\circ} C

0.0 3^{\circ} C

Views: 6,009 students

Updated on: Sep 26, 2022

Book:

Arihant Chemistry JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2002

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Lucas Discussed

Relative lowering of vapour pressure of an aqueous glucose dilute solution is found to be 0.018. Hence, elevation in boiling point is (Given, that 1 molal aqueous urea solution boils at

00.05 4^{\circ} C

at 1 atm pressure).

7 mins ago

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7 mins ago

Text solutionVerified

Δ T_{b}

for urea solution

= 0.5 4^{\circ} = K_{I} \times

molality

K_{f} = \frac{0.5 4 ^{\circ}}{1}

= 0.5 4^{\circ} kg mol m^{- 1}

\frac{Δ p}{p ^{\circ}} = \frac{wM}{mW}

\frac{w}{mW} = \frac{Δ p}{p ^{\circ} M}

= \frac{0.018}{18}

Δ T_{b} (glucose) = \frac{1000 K _{f} W}{mW}

= \frac{1000 \times 0.54 \times 0.018}{18}

= 0.5 4^{\circ} C

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Question Text	Relative lowering of vapour pressure of an aqueous glucose dilute solution is found to be 0.018. Hence, elevation in boiling point is (Given, that 1 molal aqueous urea solution boils at $00.05 4^{\circ} C$ at 1 atm pressure).
Updated On	Sep 26, 2022
Topic	Solutions
Subject	Chemistry
Class	Class 12
Answer Type	Text solution:1 Video solution: 4
Upvotes	505
Avg. Video Duration	6 min

Relative lowering of vapour pressure of an aqueous glucose dilute solution is found to be 0.018. Hence, elevation in boiling point is (Given, that 1 molal aqueous urea solution boils at $00.05 4^{\circ} C$ at 1 atm pressure).

Text solutionVerified

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Relative lowering of vapour pressure of an aqueous glucose dilute solution is found to be 0.018. Hence, elevation in boiling point is (Given, that 1 molal aqueous urea solution boils at 00.054∘C at 1 atm pressure).

Text solutionVerified

Filo tutor solutions (4)

Questions from JEE Mains 2002 - PYQs

Practice questions from Arihant Chemistry JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Practice questions from Solutions in the same exam

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Relative lowering of vapour pressure of an aqueous glucose dilute solution is found to be 0.018. Hence, elevation in boiling point is (Given, that 1 molal aqueous urea solution boils at $00.05 4^{\circ} C$ at 1 atm pressure).