Question
Pressure versus temperature graph of an ideal gas is as shown in Fig. corresponding density () versus volume ( V) graph will be :
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Text solutionVerified
As we know,
From the figure,
process A to B,
hence
now as pressure increases volume decreases ,which is happening only in option B and D.
Process B to C.
so,
ie point B and point C coincides which is happening only in option B.
hence option B is correct.
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Question Text | Pressure versus temperature graph of an ideal gas is as shown in Fig. corresponding density () versus volume ( V) graph will be : |
Answer Type | Text solution:1 |
Upvotes | 150 |