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{p}{H} of saturated solution of {B}{a}{({O}{H})}_{{{2}}} is {1

Question

$p H$ of saturated solution of $B a (O H)_{2}$ is $12$ . The value of solubility product $(K_{s p})$ of $B a (O H)_{2}$ is

4.00 \times 10^{- 6} M^{3}

4.00 \times 10^{- 7} M^{3}

5.00 \times 10^{- 7} M^{3}

5.00 \times 10^{- 6} M^{3}

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Benjamin Discussed

p H

of saturated solution of

B a (O H)_{2}

12

. The value of solubility product

(K_{s p})

B a (O H)_{2}

13 mins ago

Discuss this question LIVE

13 mins ago

Text solutionVerified

Given, pH of

B a (O H)_{2} = 12

So, pOH = 2

∴ [H^{+}] = [1 \times 10^{- 12}]

K_{w} = (H^{+}) (O H^{-})

K_{w} = 1 \times 10^{- 14}

O H^{-} = \frac{K _{ω}}{H ^{+}}

and

[O H^{-}] = \frac{1 \times 10 ^{- 14}}{1 \times 10 ^{- 12}} [∵ [H^{+}] [O H^{-}] = 1 \times 10^{- 14}]

= 1 \times 10^{- 2} m o l / L

B a (O H)_{2} \to S B a^{2 +} + 2 S 2 O H^{-}

K_{s p} = [B a^{2 +}] [O H^{-}]^{2} = [S] [2 S]^{2}

= [\frac{1 \times 10 ^{- 2}}{2}] (1 \times 10^{- 2})^{2}

= 0.5 \times 10^{- 6} = 5.0 \times 10^{- 6} M^{3}

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Question Text	$p H$ of saturated solution of $B a (O H)_{2}$ is $12$ . The value of solubility product $(K_{s p})$ of $B a (O H)_{2}$ is
Answer Type	Text solution:1
Upvotes	150