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Equilibrium in chemical processes

{C}({s}) 2 {~A}({~g})+{B}({s}) If the dissociation of C(s) is

Question

Hard

Solving time: 5 mins

$C (s) ⇌ 2 A (g) + B (s)$
If the dissociation of $C (s)$ is ' $α$ ' and $d$ is the density of the gaseous mixture in the container. Initially container have only ' $C (s)^{’}$ and the reaction is carried at constant temperature and pressure.

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Text solutionVerified

As in the gaseous mixture only A will be present so the molecular weight of the gaseous mixture will be '

M_{A}

∵ PM_{A} = dRT

where

R, P, T

are constants.
so

d \propto M_{A}

and hence it does not depend on '

α

'
so 'd' will remain constant.
Option (D) is correct.

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C (s) ⇌ 2 A (g) + B (s)

If the dissociation of

C (s)

is '

α

' and

d

is the density of the gaseous mixture in the container. Initially container have only '

C (s)^{’}

and the reaction is carried at constant temperature and pressure.

7 mins ago

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Question Text	$C (s) ⇌ 2 A (g) + B (s)$ If the dissociation of $C (s)$ is ' $α$ ' and $d$ is the density of the gaseous mixture in the container. Initially container have only ' $C (s)^{’}$ and the reaction is carried at constant temperature and pressure.
Topic	Equilibrium
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1
Upvotes	59

$C (s) ⇌ 2 A (g) + B (s)$
If the dissociation of $C (s)$ is ' $α$ ' and $d$ is the density of the gaseous mixture in the container. Initially container have only ' $C (s)^{’}$ and the reaction is carried at constant temperature and pressure.

Text solutionVerified

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C(s)⇌2 A( g)+B(s)If the dissociation of C(s) is ' α ' and d is the density of the gaseous mixture in the container. Initially container have only ' C(s)’ and the reaction is carried at constant temperature and pressure.

Text solutionVerified

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$C (s) ⇌ 2 A (g) + B (s)$
If the dissociation of $C (s)$ is ' $α$ ' and $d$ is the density of the gaseous mixture in the container. Initially container have only ' $C (s)^{’}$ and the reaction is carried at constant temperature and pressure.