Ionic radii of :

Answer: DSolution: (a) $T{i}^{4+}>M{n}^{7+}$ is the correct order of size due to lower positive charge on $T{i}^{4+}$
(b) ${.}^{37}C{l}^{-}={.}^{37}C{l}^{-}$: Isotopes with same charge have same size because isotopes differ in compositions of nuclei which do not affect the atomic/ionic radius.
(c) $K^{+}<C{l}^{-}$ is the correct order. Among isoelectronic species, anion has greater size than cation.
(d) $P^{3+}>P^{5+}$ is the correct order. For the same elements, lower the positive charge, larger the ions.