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In a buffer solution containing equal concentration of {B}^{{-

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In a buffer solution containing equal concentration of $B^{-}$ and $H B$ , the $K_{b}$ for $B^{-}$ is $10^{- 10}$ . The $p H$ of buffer solution is

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In a buffer solution containing equal concentration of

B^{-}

and

H B

, the

K_{b}

for

B^{-}

10^{- 10}

. The

p H

of buffer solution is

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Text solutionVerified

Key Idea - (i) For basic buffer,

p O H = p K_{b} + lo g . \frac{[ salt ]}{[ base ]}

(ii)

p H + p O H = 14

Given,

K_{b} = 1 \times 10^{- 10}

, [salt]=[base]

p O H = - lo g K_{b} + lo g . \frac{[ salt ]}{[ base ]}

∴ p O H = - lo g (1 \times 10^{- 10}) + lo g 1 = 10

p H + p O H = 14 [∵ concentration of [B^{-}] = [H B]

p H = 14 - 10 = 4

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Question Text	In a buffer solution containing equal concentration of $B^{-}$ and $H B$ , the $K_{b}$ for $B^{-}$ is $10^{- 10}$ . The $p H$ of buffer solution is
Answer Type	Text solution:1
Upvotes	150