If the equilibrium constant for N2(g)+O2(g)⇔2NO(g) is K , the equilibrium constant for 21N2(g)+21O2(g)⇔NO(g) will be

Question

If the equilibrium constant for  N2​(g)+O2​(g)⇔2NO(g) is K , the equilibrium    constant for  21​N2​(g)+21​O2​(g)⇔NO(g) will be

Filo · Accepted Answer

Plan As we can see the reaction for which we have to find out equilibrium constant is different only in stiochiometric coeficient as compared to the given reaction. Hence, we can find equilibrium constant for the required reaction with the help of mentioned equilibrium constant in the problem.
Given, equilibrium constant for the reaction.

N_{2} (g) + O_{2} (g) \Leftrightarrow 2 N O (g) i s K

.

K = \frac{[ N O ] ^{2}}{[ N O _{2} ] [ O _{2} ]}

.....(i)
Let equilibrium constant for the reaction.

\frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) \Leftrightarrow N O (g) i s K

'.
i.e.,

K^{'} = \frac{[ N O ]}{[ N O ] ^{1 / 2} [ O _{2} ] ^{1 / 2}}

On squareing both sides

K^{'}^{2} = \frac{[ N O ] ^{2}}{[ N O ] [ O _{2} ]}

.....(ii)
On comparing Eqs.(i) and (ii), we get

K = K^{2}

or

K^{'} = K

Question Text	If the equilibrium constant for $N_{2} (g) + O_{2} (g) \Leftrightarrow 2 N O (g)$ is K , the equilibrium $constant for \frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) \Leftrightarrow N O (g)$ will be
Answer Type	Text solution:1
Upvotes	150

If the equilibrium constant for
$N_{2} (g) + O_{2} (g) \Leftrightarrow 2 N O (g)$ is K , the equilibrium
$constant for \frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) \Leftrightarrow N O (g)$ will be

Text solutionVerified

Practice questions from similar books

If the equilibrium constant for N2​(g)+O2​(g)⇔2NO(g) is K , the equilibrium constant for 21​N2​(g)+21​O2​(g)⇔NO(g) will be

Text solutionVerified

Practice questions from similar books

If the equilibrium constant for
$N_{2} (g) + O_{2} (g) \Leftrightarrow 2 N O (g)$ is K , the equilibrium
$constant for \frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) \Leftrightarrow N O (g)$ will be