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How many moles of electrons weigh {1}{k}{g}?

Question

How many moles of electrons weigh $1 k g$ ?

6.023 \times 10^{23}

\frac{1}{9.108} \times 10^{31}

\frac{6.023}{9.108} \times 10^{54}

\frac{1}{9.108 \times 6.023} \times 10^{8}

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Text solutionVerified

Answer: DSolution: Mass of an electron =

9.108 \times 10^{- 31} k g

∵ 9.108 \times 10^{- 31} k g = 1.0 electron

∴ 1 k g = \frac{1}{9.108 \times 10 ^{- 31}} electrons = \frac{10 ^{31}}{9.108} \times \frac{1}{6.023 \times 10 ^{23}}

= \frac{1}{9.108 \times 6.023} \times 10^{8}

mole of electrons

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Question Text	How many moles of electrons weigh $1 k g$ ?
Answer Type	Text solution:1
Upvotes	150