Graph between logx/m and logp is a straight line inclined at an angle of 45∘ . When pressure is 0.5atm and 1nk=0.693, the amount of solute adsorbed per gram of adsorbent will be:

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Question

Graph between $lo g x / m$ and $lo g p$ is a straight line inclined at an angle of $45^{\circ}$ . When pressure is $0.5 a t m$ and $1 n k = 0.693$ , the amount of solute adsorbed per gram of adsorbent will be:

1.5

0.25

2.5

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Graph between

lo g x / m

and

lo g p

is a straight line inclined at an angle of

45^{\circ}

. When pressure is

0.5 a t m

and

1 n k = 0.693

, the amount of solute adsorbed per gram of adsorbent will be:

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Question Text	Graph between $lo g x / m$ and $lo g p$ is a straight line inclined at an angle of $45^{\circ}$ . When pressure is $0.5 a t m$ and $1 n k = 0.693$ , the amount of solute adsorbed per gram of adsorbent will be:
Answer Type	Video solution: 1
Upvotes	150