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Chemistry Part-I

Coordination Compounds

FeSO_{4} solution mixed with (NH_{4})_{2}SO_{4} solution in 1:

Chemistry Part-I

Class 12

NCERT

Chapter 1: The Solid State

31 questions

Chapter 2: Solutions

54 questions

Chapter 3: Electrochemistry

28 questions

Chapter 4: Chemical Kinetics

40 questions

Chapter 5: Surface Chemistry

27 questions

Chapter 6: General Principles and Processes of Isolation of Elements

30 questions

Chapter 7: The p-Block Elements

62 questions

Chapter 8: The d-and f-Block Elements

48 questions

Chapter 9: Coordination Compounds

38 questions

Draw the structures of optical isomers of:
(i)

[C r (C_{2} O_{4})_{3}]^{3 -}

(ii)

[PtC l_{2} (e n)_{2}]^{2 +}

(iii)

[C r (N H_{3})_{2} C l_{2} (e n)]^{+}

F e S O_{4}

solution mixed with

(N H_{4})_{2} S O_{4}

solution in

1 : 1

molar ratio gives the test of

F e^{2 +}

ion but

C u S O_{4}

solution mixed with aqueous ammonia in

1 : 4

molar ratio does not give the test of

C u^{2 +}

ion. Explain why?

A solution of

[N i (H_{2} O)_{6}]^{2 +}

is green but a solution of

[N i (CN)_{4}]^{2 -}

is colourless, Explain.

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Question

Easy

Solving time: 2 mins

$F e S O_{4}$ solution mixed with $(N H_{4})_{2} S O_{4}$ solution in $1 : 1$ molar ratio gives the test of $F e^{2 +}$ ion but $C u S O_{4}$ solution mixed with aqueous ammonia in $1 : 4$ molar ratio does not give the test of $C u^{2 +}$ ion. Explain why?

Views: 5,779 students

Updated on: Feb 27, 2023

Book:

Chemistry Part-I (NCERT)

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Daniel Discussed

F e S O_{4}

solution mixed with

(N H_{4})_{2} S O_{4}

solution in

1 : 1

molar ratio gives the test of

F e^{2 +}

ion but

C u S O_{4}

solution mixed with aqueous ammonia in

1 : 4

molar ratio does not give the test of

C u^{2 +}

ion. Explain why?

11 mins ago

Discuss this question LIVE

11 mins ago

Text solutionVerified

Ferrous sulphate and ammonium sulphate forms Mohr's salt (a double salt) which gives free ferrous ions in solution.

Copper forms complex with ammonia. Free cupric ions are not present in solution.

F e S O_{4} + (N H_{4})_{2} S O_{4} + 6 H_{2} O \to F e S O_{4} (N H_{4})_{2} S O_{4} .6 H_{2} O (M o h r^{'} s s a lt) C u S O_{4} + 4 N H_{3} + 5 H_{2} O \to [C u (N H_{3})_{4} S O_{4}] 5 H_{2} O

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Practice more questions from Chemistry Part-I (NCERT)

Draw the structures of optical isomers of:
(i)

[C r (C_{2} O_{4})_{3}]^{3 -}

(ii)

[PtC l_{2} (e n)_{2}]^{2 +}

(iii)

[C r (N H_{3})_{2} C l_{2} (e n)]^{+}

F e S O_{4}

solution mixed with

(N H_{4})_{2} S O_{4}

solution in

1 : 1

molar ratio gives the test of

F e^{2 +}

ion but

C u S O_{4}

solution mixed with aqueous ammonia in

1 : 4

molar ratio does not give the test of

C u^{2 +}

ion. Explain why?

A solution of

[N i (H_{2} O)_{6}]^{2 +}

is green but a solution of

[N i (CN)_{4}]^{2 -}

is colourless, Explain.

View all

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Question Text	$F e S O_{4}$ solution mixed with $(N H_{4})_{2} S O_{4}$ solution in $1 : 1$ molar ratio gives the test of $F e^{2 +}$ ion but $C u S O_{4}$ solution mixed with aqueous ammonia in $1 : 4$ molar ratio does not give the test of $C u^{2 +}$ ion. Explain why?
Updated On	Feb 27, 2023
Topic	Coordination Compounds
Subject	Chemistry
Class	Class 12
Answer Type	Text solution:1 Video solution: 4
Upvotes	376
Avg. Video Duration	5 min

$F e S O_{4}$ solution mixed with $(N H_{4})_{2} S O_{4}$ solution in $1 : 1$ molar ratio gives the test of $F e^{2 +}$ ion but $C u S O_{4}$ solution mixed with aqueous ammonia in $1 : 4$ molar ratio does not give the test of $C u^{2 +}$ ion. Explain why?

Text solutionVerified

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FeSO4​ solution mixed with (NH4​)2​SO4​ solution in 1:1 molar ratio gives the test of Fe2+ ion but CuSO4​ solution mixed with aqueous ammonia in 1:4 molar ratio does not give the test of Cu2+ ion. Explain why?

Text solutionVerified

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$F e S O_{4}$ solution mixed with $(N H_{4})_{2} S O_{4}$ solution in $1 : 1$ molar ratio gives the test of $F e^{2 +}$ ion but $C u S O_{4}$ solution mixed with aqueous ammonia in $1 : 4$ molar ratio does not give the test of $C u^{2 +}$ ion. Explain why?