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Chemistry Part-I

Coordination Compounds

[Fe(CN)_{6}]^{4-} and [Fe(H_{2}O)_{6}]^{2+} are of different c

Chemistry Part-I

Class 12

NCERT

Chapter 1: The Solid State

31 questions

Chapter 2: Solutions

54 questions

Chapter 3: Electrochemistry

28 questions

Chapter 4: Chemical Kinetics

40 questions

Chapter 5: Surface Chemistry

27 questions

Chapter 6: General Principles and Processes of Isolation of Elements

30 questions

Chapter 7: The p-Block Elements

62 questions

Chapter 8: The d-and f-Block Elements

48 questions

Chapter 9: Coordination Compounds

38 questions

[C r (N H_{3})_{6}]^{3 +}

is paramagnetic while

[N i (CN)_{4}]^{2 -}

is diamagnetic. Explain why?

[F e (CN)_{6}]^{4 -}

and

[F e (H_{2} O)_{6}]^{2 +}

are of different colours in dilute solutions. Why?

Discuss the nature of bonding in metal carbonyls.

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Question

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Solving time: 3 mins

$[F e (CN)_{6}]^{4 -}$ and $[F e (H_{2} O)_{6}]^{2 +}$ are of different colours in dilute solutions. Why?

Name: Video solution 1: [Solved] [Fe(CN)6]4− and [Fe(H2O)6]2+ are of different colours in dilute solutions. Why? - Chemistry Part-I
Uploaded: 2023-02-19T12:46:07.000Z
Duration: 2 min
Description: Video solution 1: [Solved] [Fe(CN)6]4− and [Fe(H2O)6]2+ are of different colours in dilute solutions. Why? - Chemistry Part-I

Views: 6,367 students

Updated on: Feb 19, 2023

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Chemistry Part-I (NCERT)

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Levi Discussed

[F e (CN)_{6}]^{4 -}

and

[F e (H_{2} O)_{6}]^{2 +}

are of different colours in dilute solutions. Why?

6 mins ago

Discuss this question LIVE

6 mins ago

Text solutionVerified

In both complexes, iron has +2 oxidation state with outer electronic configuration of

3 d^{6}

and four unpaired electrons.
In presence of weak filed water ligand, these unpaired electrons do not pair up. However, in presence of strong field cyanide ligand, the unpaired electrons pair up and there are no unpaired electrons.
In two complexes, there is difference in the number of unpaured electrons. This gives rise to different colours.

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Practice more questions from Chemistry Part-I (NCERT)

[C r (N H_{3})_{6}]^{3 +}

is paramagnetic while

[N i (CN)_{4}]^{2 -}

is diamagnetic. Explain why?

[F e (CN)_{6}]^{4 -}

and

[F e (H_{2} O)_{6}]^{2 +}

are of different colours in dilute solutions. Why?

Discuss the nature of bonding in metal carbonyls.

View all

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Question Text	$[F e (CN)_{6}]^{4 -}$ and $[F e (H_{2} O)_{6}]^{2 +}$ are of different colours in dilute solutions. Why?
Updated On	Feb 19, 2023
Topic	Coordination Compounds
Subject	Chemistry
Class	Class 12
Answer Type	Text solution:1 Video solution: 2
Upvotes	225
Avg. Video Duration	9 min

$[F e (CN)_{6}]^{4 -}$ and $[F e (H_{2} O)_{6}]^{2 +}$ are of different colours in dilute solutions. Why?

Text solutionVerified

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