Equal masses of H2, O2 and methane have been taken in a container of volume V at temperature 27∘C in identical conditions. The ratio of the volume of gases H2:O2 : methane would be

Question

Equal masses of H2​, O2​ and methane have been taken in a container of volume V at temperature 27∘C in identical conditions. The ratio of the volume of gases H2​:O2​ : methane would be

Filo · Accepted Answer

According to Avogadro's hypothesis,
Volume of a gas

(V) \propto

number of moles (n)
Therefore, the ratio of the volumes of gases can be determined in terms of their moles.

∴ The ratio of volumes of H_{2} : O_{2} : methane (C H_{4}) is given by

V_{H_{2}} : V_{O_{2}} : V_{C H_{4}} = n_{H_{2}} : n_{O_{2}} : n_{C H_{4}}

\Rightarrow V_{H_{2}} : V_{O_{2}} : V_{C H_{4}} := \frac{m _{H_{2}}}{M _{H_{2}}} : \frac{m _{O_{2}}}{M _{O_{2}}} : \frac{m _{C H_{4}}}{M _{C H_{4}}}

Given,

m_{H_{2}} = m_{O_{2}} = m_{C H_{4}} = m

[∵ n = \frac{mass}{molar mass}]

Thus,

V_{H_{2}} : V_{O_{2}} : V_{C H_{4}} = \frac{m}{2} : \frac{m}{32} : \frac{m}{16} = 16 : 1 : 2

Question Text	Equal masses of $H_{2}$ , $O_{2}$ and methane have been taken in a container of volume $V$ at temperature $27^{\circ} C$ in identical conditions. The ratio of the volume of gases $H_{2} : O_{2}$ : methane would be
Answer Type	Text solution:1
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Equal masses of $H_{2}$ , $O_{2}$ and methane have been taken in a container of volume $V$ at temperature $27^{\circ} C$ in identical conditions. The ratio of the volume of gases $H_{2} : O_{2}$ : methane would be

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Practice questions from similar books

Equal masses of H2​, O2​ and methane have been taken in a container of volume V at temperature 27∘C in identical conditions. The ratio of the volume of gases H2​:O2​ : methane would be

Text solutionVerified

Practice questions from similar books

Equal masses of $H_{2}$ , $O_{2}$ and methane have been taken in a container of volume $V$ at temperature $27^{\circ} C$ in identical conditions. The ratio of the volume of gases $H_{2} : O_{2}$ : methane would be