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At {S}{T}{P}, the order of mean square velocity of molecules o

Question

At $S T P$ , the order of mean square velocity of molecules of $H_{2}$ , $N_{2}$ , $O_{2}$ , and $H B r$ is

H_{2} < N_{2} < O_{2} < H B r

H B r < O_{2} < N_{2} < H_{2}

H_{2} < N_{2} = O_{2} < H B r

H B r < O_{2} < H_{2} < N_{2}

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Henry Discussed

S T P

, the order of mean square velocity of molecules of

H_{2}

N_{2}

O_{2}

, and

H B r

9 mins ago

Discuss this question LIVE

9 mins ago

Text solutionVerified

The root mean square velocity of gas molecule at STP given by

U_{r m s} = \frac{3 R T}{M}

∴

As the molar mass of gas increases, then

U_{r m s}

will decrease, so the order of

U_{r m s}

of these gases is

H B r < O_{2} < N_{2} < H_{2}

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Question Text	At $S T P$ , the order of mean square velocity of molecules of $H_{2}$ , $N_{2}$ , $O_{2}$ , and $H B r$ is
Answer Type	Text solution:1
Upvotes	150