As per this diagram a point charge $+ q$ is placed at the origin $O$ . Work done in taking another point charge $- Q$ from the point $A (0, a)$ to another point $B (a, 0)$ along the staight path $A B$ is:

zero

(\frac{- q Q}{4 π ϵ _{0}} \frac{1}{a ^{2}}) 2 a

(\frac{q Q}{4 π ϵ _{0}} \frac{1}{a ^{2}}) \frac{a}{2}

(\frac{q Q}{4 π ϵ _{0}} \frac{1}{a ^{2}}) 2 a

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Noah Discussed

As per this diagram a point charge

+ q

is placed at the origin

O

. Work done in taking another point charge

- Q

from the point

A (0, a)

to another point

B (a, 0)

along the staight path

A B

is:

9 mins ago

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