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Aqueous {Fe} (III) ion develops intense red colour with {SCN}^

Question

Aqueous $Fe$ (III) ion develops intense red colour with $SCN^{-}$ while $Fe$ (II) does not. It is due to (a) $Fe$ (III) ion forms a charge transfer complex with $SCN^{-}$ ions (b) $Fe$ (III) is reduced to $Fe$ (I) which is deep red in colour (c) $SCN^{-}$ ion oxidises to $CN^{-}$ ion that forms red complex with $Fe$ (III) ion (d) $SCN^{-}$ ion does not form any complex with $Fe$ (II) ion

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Aqueous

Fe

(III) ion develops intense red colour with

SCN^{-}

while

Fe

(II) does not. It is due to (a)

Fe

(III) ion forms a charge transfer complex with

SCN^{-}

ions (b)

Fe

(III) is reduced to

Fe

(I) which is deep red in colour (c)

SCN^{-}

ion oxidises to

CN^{-}

ion that forms red complex with

Fe

(III) ion (d)

SCN^{-}

ion does not form any complex with

Fe

(II) ion

10 mins ago

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Text solutionVerified

(a)

Fe (III)

ion forms a charge transfer complex with

SCN^{-}

ions

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Question Text	Aqueous $Fe$ (III) ion develops intense red colour with $SCN^{-}$ while $Fe$ (II) does not. It is due to (a) $Fe$ (III) ion forms a charge transfer complex with $SCN^{-}$ ions (b) $Fe$ (III) is reduced to $Fe$ (I) which is deep red in colour (c) $SCN^{-}$ ion oxidises to $CN^{-}$ ion that forms red complex with $Fe$ (III) ion (d) $SCN^{-}$ ion does not form any complex with $Fe$ (II) ion
Topic	Coordination Compounds
Subject	Chemistry
Class	Class 12
Answer Type	Text solution:1
Upvotes	35

Text solutionVerified

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