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A solution which is {10}^{{-{3}}}{M} each in {M}{n}^{{{2}+}},{

Question

A solution which is $10^{- 3} M$ each in $M n^{2 +}, F e^{2 +}, Z n^{2 +}$ , and $H g^{2 +}$ it treated with $10^{- 16} M$ sulphide ion. If the $K_{s p}$ of $M n S, F e S, Z n S$ and $H g S$ are $10^{- 15}, 10^{- 23}, 10^{- 20}$ ,and $10^{- 54}$ , respectively, which one will precipitate first?

F e S

M g S

H g S

Z n S

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Emma Discussed

A solution which is

10^{- 3} M

each in

M n^{2 +}, F e^{2 +}, Z n^{2 +}

, and

H g^{2 +}

it treated with

10^{- 16} M

sulphide ion. If the

K_{s p}

M n S, F e S, Z n S

and

H g S

are

10^{- 15}, 10^{- 23}, 10^{- 20}

,and

10^{- 54}

, respectively, which one will precipitate first?

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Text solutionVerified

Answer: C::D

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Question Text	A solution which is $10^{- 3} M$ each in $M n^{2 +}, F e^{2 +}, Z n^{2 +}$ , and $H g^{2 +}$ it treated with $10^{- 16} M$ sulphide ion. If the $K_{s p}$ of $M n S, F e S, Z n S$ and $H g S$ are $10^{- 15}, 10^{- 23}, 10^{- 20}$ ,and $10^{- 54}$ , respectively, which one will precipitate first?
Answer Type	Text solution:1
Upvotes	150