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A first-order reaction is carried out with an initial concentr

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A first-order reaction is carried out with an initial concentration of $10$ mole per litre and $80$ % of the reactant changes into the product. Now if the same reaction is carried out with an initial concentration of $5$ mol per litre, the percentage of the reactant changing to the product is:

40

80

160

cannot be calculated

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A first-order reaction is carried out with an initial concentration of

10

mole per litre and

80

% of the reactant changes into the product. Now if the same reaction is carried out with an initial concentration of

5

mol per litre, the percentage of the reactant changing to the product is:

7 mins ago

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7 mins ago

Text solutionVerified

a_{0} = 10 M

80%

changed into product

∴ a_{t} = 10 \frac{10 \times 80}{100} = 2 M

a_{0} = 5 M

, In the same time duration same percentage of initial concentration changes into products because in first order reaction is independent from initial concentration.

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Question Text	A first-order reaction is carried out with an initial concentration of $10$ mole per litre and $80$ % of the reactant changes into the product. Now if the same reaction is carried out with an initial concentration of $5$ mol per litre, the percentage of the reactant changing to the product is:
Answer Type	Text solution:1
Upvotes	153

A first-order reaction is carried out with an initial concentration of 10 mole per litre and 80% of the reactant changes into the product. Now if the same reaction is carried out with an initial concentration of 5 mol per litre, the percentage of the reactant changing to the product is:

Text solutionVerified

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A first-order reaction is carried out with an initial concentration of $10$ mole per litre and $80$ % of the reactant changes into the product. Now if the same reaction is carried out with an initial concentration of $5$ mol per litre, the percentage of the reactant changing to the product is: