1 kg of water is heated from 40 C to 70 C, If its volume remains constant, then the change in internal energy is (specific heat of water = 4148 J $k g^{- 1} K^{- 1})$

2.44 \times 10^{5}

1.62 \times 10^{5}

1.24 \times 10^{5}

2.62 \times 10^{5}

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1 kg of water is heated from 40 C to 70 C, If its volume remains constant, then the change in internal energy is (specific heat of water = 4148 J

k g^{- 1} K^{- 1})

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Text solutionVerified

Since volume does not change as the energy supplied is used to change the internal energy.

Δ E = Δ U = m Cθ = 1 \times 4148 \times 30 = 1.24 \times 1 0^{5} J

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Question Text	1 kg of water is heated from 40 C to 70 C, If its volume remains constant, then the change in internal energy is (specific heat of water = 4148 J $k g^{- 1} K^{- 1})$
Answer Type	Text solution:1
Upvotes	155