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0.220g of a gas occupies a volume of 112mL at a pressure of 1

Question

0.220g of a gas occupies a volume of 112mL at a pressure of 1 bar and temperature of 273 K. The gas can be:

NO_{2}

N_{2} O

CO_{2}

C_{3} H_{8}

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0.220g of a gas occupies a volume of 112mL at a pressure of 1 bar and temperature of 273 K. The gas can be:

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Text solutionVerified

moles

= \frac{0.220}{x}

[Let x = mol. wt. of gas]

1 moles consist 22.4L

\frac{0.220}{x}

mole consist

\frac{0.220}{x} \times 22.4 = \frac{4.928}{x} L

\frac{4.928}{x} = 0.112

x = \frac{4.928}{0.122} = 44 g m / m o l

∴ x = 44 g / m o l

which is not wt of

C O_{2}

Hence option C is correct.

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Question Text	0.220g of a gas occupies a volume of 112mL at a pressure of 1 bar and temperature of 273 K. The gas can be:
Answer Type	Text solution:1
Upvotes	151