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Solving time: 1 mins

Find out the wrongly matched pair.

A
Primary metabolite - Ribose

B
Secondary metabolite - Anthocyanins

C
Protein - Insulin

D
Cellulose - Heteropolymer

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Correct answer is D
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Consider a situation where you have a parental cross with the mother and father phenotypes listed below. Remember that the genotype for the wild-type parent is always homozygous. The counts of the F offspring are listed in Table 1. Two randomly selected individuals are selected and mated to produce a set of F individuals. If you test the F counts to determine whether they are consistent with an autosomal recessive mode of inheritance, what is your decision? Use a 0.05 significance level. PARENTAL CROSS: Parental cross: Mother with wild-type phenotype, Father with disease phenotype. Table 1. F1 DATA Gender Phenotype Male Disease 0 Female Wild-type 24 Male Disease 0 Female Wild-type 30 Table 2. F2 DATA Gender Phenotype Male Disease 100 Female Wild-type 297 Male Disease 96 Female Wild-type 315 Do not reject the null hypothesis that the F data are consistent with an autosomal recessive mode of inheritance. Chi-square goodness of fit test p-value > 0.05. Reject the null hypothesis that the F data are consistent with an autosomal recessive mode of inheritance; the true mode of inheritance is autosomal dominant. Do not reject the null hypothesis that the F data are consistent with an autosomal recessive mode of inheritance; chi-square goodness of fit test statistic value is between 5 and 10. Reject the null hypothesis that the F data are consistent with an autosomal recessive mode of inheritance; the p-value for the chi-square goodness of fit test > 0.05. Reject the null hypothesis that the F data are consistent with an autosomal recessive mode of inheritance; the p-value for the chi-square goodness of fit test < 0.05.
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Question Text
Find out the wrongly matched pair.
Updated OnFeb 9, 2024
TopicBiomolecules
SubjectBiology
ClassClass 11
Answer TypeText solution:1 Video solution: 1
Upvotes87
Avg. Video Duration3 min