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A population is in Hardy- Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele A is 0.7, the genotype frequency of Aa is
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For a gene with two alleles, (dominant) and a (recessive), if the frequency of is and the frequency of is , then the the frequencies of the three possible genotypes (, ) can be expressed by the Hardy-Weinberg equation :
+ 2pq + = 1
where, = frequency of (homozygous dominant) individuals, 2 = frequency of (heterozygous) individuals and = frequency of (homozygous recessive) individuals.
The equation can be used to calculate allele frequencies if the numbers of homozygous recessive individuals in the population is known.
Here, p = 0.7 and q = 0.3 (given)
2 (frequency of heterozygote) = 2 × 0.7 × 0.3 = 0.42
+ 2pq + = 1
where, = frequency of (homozygous dominant) individuals, 2 = frequency of (heterozygous) individuals and = frequency of (homozygous recessive) individuals.
The equation can be used to calculate allele frequencies if the numbers of homozygous recessive individuals in the population is known.
Here, p = 0.7 and q = 0.3 (given)
2 (frequency of heterozygote) = 2 × 0.7 × 0.3 = 0.42
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| Question Text | A population is in Hardy- Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele A is 0.7, the genotype frequency of Aa is |
| Updated On | Aug 27, 2022 |
| Topic | Evolution |
| Subject | Biology |
| Class | Class 12 |
| Answer Type | Text solution:1 Video solution: 2 |
| Upvotes | 340 |
| Avg. Video Duration | 3 min |
