A projectile is given an initial velocity of (i^+2j^)m/s, where i^ is along the ground and j^ is along the vertical. If g=10 m/s2, the equation of its trajectory is :

Given:Velocity of projection, u=i^+2j^=uxi^+uyj^Ux=1m/s X = 1t = t,…(1) Uy = 2 m/sy=Uyt+21gt2 y=2t−2110t2 …(2) put the value of t from eqn (1) to eqn (2)we get,y=2x−5x2

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A projectile is given an initial velocity of ({i}+2 {j}) {m} /

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A projectile is given an initial velocity of $(\hat{i} + 2 \hat{j}) m / s$ , where $\hat{i}$ is along the ground and $\hat{j}$ is along the vertical. If $g = 10 m / s^{2}$ , the equation of its trajectory is :

y = x - 5 x^{2}

y = 2 x - 5 x^{2}

4 y = 2 x - 5 x^{2}

4 y = 2 x - 25 x^{2}

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Updated on: Jun 27, 2023

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Amelia Discussed

A projectile is given an initial velocity of

(\hat{i} + 2 \hat{j}) m / s

, where

\hat{i}

is along the ground and

\hat{j}

is along the vertical. If

g = 10 m / s^{2}

, the equation of its trajectory is :

7 mins ago

Discuss this question LIVE

7 mins ago

Text solutionVerified

Given:
Velocity of projection,

u = \hat{i} + 2 \hat{j} = u_{x} \hat{i} + u_{y} \hat{j}

U_{x} = 1 m / s

X = 1t = t,

\dots (1)

U_{y}

= 2 m/s

y = U_{y} t + \frac{1}{2} g t^{2}

y = 2 t - \frac{1}{2} 10 t^{2}

\dots (2)

put the value of t from eqn (1) to eqn (2)
we get,

y = 2 x - 5 x^{2}

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Question Text	A projectile is given an initial velocity of $(\hat{i} + 2 \hat{j}) m / s$ , where $\hat{i}$ is along the ground and $\hat{j}$ is along the vertical. If $g = 10 m / s^{2}$ , the equation of its trajectory is :
Updated On	Jun 27, 2023
Topic	Motion in a Plane
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 24
Upvotes	2594
Avg. Video Duration	9 min

A projectile is given an initial velocity of $(\hat{i} + 2 \hat{j}) m / s$ , where $\hat{i}$ is along the ground and $\hat{j}$ is along the vertical. If $g = 10 m / s^{2}$ , the equation of its trajectory is :

Text solutionVerified

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A projectile is given an initial velocity of $(\hat{i} + 2 \hat{j}) m / s$ , where $\hat{i}$ is along the ground and $\hat{j}$ is along the vertical. If $g = 10 m / s^{2}$ , the equation of its trajectory is :